Handling Multiple NPC's Actions With a Single Die Roll [in AD&D] by Joel Hahn The following is intended to be compatible with D&D, but can be used, usually with no or little modification, with just about any RPG. Have you ever tried to DM a party caught in an ambush of 50 archers but couldn't figure an quick, easy way to resolve the NPC's turns in under two hours each, but also don't want to crack open the Battlesystem rules? Or had 10 Imperial Guards try to climb a rock face after our heroes but didn't want to roll skill checks for each and every one? Here are two solutions for using one die roll to determine multiple actions of NPCs: =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= Method 1) Use Torg's "Many on One" table, modified slightly #Char Bonus | Result #Succ ----- ------ | ------ ----- 1 +0 | DN 1 2 +2 | DN+2 2 3-4 +3 | DN+4 3-4 5-6 +4 | DN+6 5-6 7-10 +5 | DN+8 7-10 11-15 +6 | DN+10 11-15 #Char = number of characters with equal THAC0 & modifers whose actions will be resolved with this roll Bonus = a bonus applied to the roll Result = How much the die roll beats the Difficulty Number (DN) by #Succ = number of characters that succeed at the action To use this table, first group the NPCs into groups with equal THAC0s and other modifiers (e.g. fighting on higher ground), and then split those groups, if necessary, into groups of 15 or smaller. Check the left side of the table to see what additional modifier will be applied to the die roll due to number of characters attempting the action. Roll one d20, applying the modifier from the "Bonus to Hit" column, as well as any situational modifiers. Compare the resulting total to the third column. The DN is the number needed for a single person in the same situation to succeed. For attacks, the Difficulty Number is the opponent's AC. The number in the same row under #Succ is the number of NPCs that succeed. When that number is a range, the DM either chooses an number appropriate for the given situation, or flips a coin or rolls a d4 or d5 to determine exactly how many NPC's succeed. Example #1: Ten 1st-level archers are firing on Rast, a fighter in chainmail with an AC of 5. The bonus for 10 NPCs is +5. The roll comes up 9. 9+5 = 14, but the archers needed a total of 15 (because of Rast's AC) for any of them to hit, thus they all miss. However, on the second turn, the die comes up 15; 15+5 = 20, which beats the number needed to hit Rast by 5. The DN+5 line under #Succ is 3-4, so 3-4 of the ten archers succeed. The DM decides that 4 archers actually succeed and rolls damage accordingly. Example #2: Five guards attempt to pursue our heroes over a thin foot-bridge across a chasm in the heart of an underground complex. The DM determines that it takes a roll of 14 to make it successfully across to the other side. The bonus for 5 NPCs is +4. The DM gives the guards a bonus of +1 because of their familiarity with the bridge. The roll comes up 6. 6+4+1 = 11, which is not enough for any to succeed, so they all slip and fall screaming into the bottomless chasm. If the roll had been a 19, 19+4+1 = 24; the roll would have beaten the difficulty of 14 by 10, so all five would have succeeded. This system can also be used to determine the outcome of PC actions, though I do not recommend it for such, as players usually like to determine success & failure for themselves. If you are running a campaign where the DM is the only one rolling dice, then this may be something to look into, especially in situations such as scaling a rock face or simple combats involving equal-ability party members and a single opponent. =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= Method 2) Multiple NPCs Success Table For those people who really like tables (and a little bit of easy calculation), here's another solution, based on probability theory, to the problem of resolving many NPC's actions, especially attacks. -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 0 1-97 1-77 1-59 1-44 1-33 1-24 1-17 1-12 1-8 1-5 1-3 1 98 78-98 60-92 45-83 34-74 25-63 18-53 13-43 9-34 6-26 4-18 2 99 99 93-98 84-98 75-94 64-90 54-84 44-76 35-68 27-59 19-50 3 100 100 99 99 95-98 91-98 85-97 77-94 69-91 60-87 51-82 4 * * 100 100 99 99 98-99 95-99 92-98 88-98 83-97 5 * * * * 100 100 100 100 99-100 99-100 98-100 1 2 3 4 5 6 7 8 9 10 0 1-2 1-2 1 1 1 1 * * * * 1 3-13 3-9 2-6 2-3 2 2 1 1 * * 2 14-41 10-32 7-24 4-16 3-10 3-6 2 2 1 1 3 42-74 33-66 25-57 17-47 11-37 7-26 3-17 3-8 2 2 4 75-95 67-92 58-88 48-83 38-76 27-67 18-56 9-41 3-23 3 5 96-100 93-100 89-100 84-100 77-100 68-100 57-100 42-100 24-100 4-100 Start with 0. Subtract any negative modifiers and add any positive modifiers to the success roll[1]. Find the column marked by the result. Divide the NPCs into groups of 5 (or multiples of 5[2]) so that all of the characters in a group will use the same column[3]. Roll d100 for each group and find which row the result is in. That is the number of characters who succeed. [1]For combat, subtract (10-PC's AC) and add (20-NPC's THAC0). [2] If using multiples of 5, be sure to multiply the row headers by the same amount. [3] If a group has less than 5 NPCs in it, you can either roll separate checks for each as per the normal rules, or scale the total in that group to the table: If there are 2, treat results of 1-3 as 1, and 4-5 as 2 If there are 3, treat results of 1-2 as 1, 3-4 as 2, and 5 as 3 If there are 4, treat results normally, except for 5, which is treated as a result of 4. Example #1: 5 tenth-level archers are attempting to fire at Rast, a fighter who has an AC of -1 due to his enchanted full plate armor. The archers' THAC0 is 11. 10-(-1) = 11, and 20-11 = 9; 0-11+9 = -2. The DM rolls d100; the result is 37. A 37 in the -2 column shows that 2 of the 5 succeed, and the DM rolls damage accordingly. Example #2: 14 tenth-level archers are attempting to fire at Rast, a fighter who has an AC of -1 due to his enchanted full plate armor. The archers have a THAC0 of 11. The DM splits the archers into a group of ten and a group of four. As above, the -2 column is used to determine the result. The DM rolls 2d100, one for each group. The first roll is 72, the second is 20. Therefore, five or six archers (3 is treated as 5-6 for the purposes of a group of ten NPCs) from the first group and one from the second group succeed, The DM decides that five from the first group actually succeed, making a total of six successful attacks. The DM rolls damage accordingly. Example #3: Five guards attempt to pursue our heroes over a thin foot-bridge across a raging river in the heart of an underground complex. The bridge is slippery from the spray from the river, so the DM assigns a -7 to the difficulty. There are no positive modifiers in this case, so the -7 column is used. As you can see from the table, the difficulty is so great that it is impossible for all five guards to succeed. The DM rolls a d100 and gets a 53, which means that only 1 of the guards succeeds; the other four fall into the swift current and are swiftly carried away to parts unknown. This method, like the first, can also be used in some circumstances to determine the outcome of PC actions as well as NPC. =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-= If you have any feedback, especially if it regards Method #2, please either mail it to Aardy, or post it to rec.games.frp.dnd

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